2p^2-7p-85=0

Solution for 2p^2-7p-85=0 equation:

2p^2-7p-85=0

a = 2; b = -7; c = -85;
Δ = b2-4ac
Δ = -72-4·2·(-85)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-27}{2*2}=\frac{-20}{4}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+27}{2*2}=\frac{34}{4}
=8+1/2
$